CARNOT EFFICIENCY
Hi, I'm new in this forum .
I have a simple but tricky question.
If the the Carnot cycle has the major efficiency rather than every other cycle and it's efficiency is lower than 1 .... that means that the rate of temperature (Temperature in Kelvin scale) is bigger than 1..... but in order to respect the idea of isoentropic process , the heat transformation has to be happen between an infinitesimal difference of Temperature .
So what I have understand , is that the temperature has not to change between a point A to a point B ..... so why The rate of temperature in the carnot efficency is not equal to 1.
eff (carnot) = 1- (Tb/Ta) I hope my question is clear and well asked.
Thank you beforehand .
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Isentropic doesn't mean at constant temperature. Entropy depends on temperature and pressure. For instance, turbine (work is generated): the process could be isoentropic with higher pressure and temperature at the input and lower pressure and temperature at the output. Mikhail